y=ln(5x^2+4y^2)

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Solution for y=ln(5x^2+4y^2) equation: 


Simplifying
y = ln(5x2 + 4y2)
y = (5x2 * ln + 4y2 * ln)
y = (5lnx2 + 4lny2)

Solving
y = 5lnx2 + 4lny2

Solving for variable 'y'.

Reorder the terms:
-5lnx2 + -4lny2 + y = 5lnx2 + 4lny2 + -5lnx2 + -4lny2

Reorder the terms:
-5lnx2 + -4lny2 + y = 5lnx2 + -5lnx2 + 4lny2 + -4lny2

Combine like terms: 5lnx2 + -5lnx2 = 0
-5lnx2 + -4lny2 + y = 0 + 4lny2 + -4lny2
-5lnx2 + -4lny2 + y = 4lny2 + -4lny2

Combine like terms: 4lny2 + -4lny2 = 0
-5lnx2 + -4lny2 + y = 0

The solution to this equation could not be determined.

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